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/* Copyright (C) 1996-2016 Free Software Foundation, Inc.
   Contributed by Richard Henderson (rth@tamu.edu)
   This file is part of the GNU C Library.

   The GNU C Library is free software; you can redistribute it and/or
   modify it under the terms of the GNU Lesser General Public
   License as published by the Free Software Foundation; either
   version 2.1 of the License, or (at your option) any later version.

   The GNU C Library is distributed in the hope that it will be useful,
   but WITHOUT ANY WARRANTY; without even the implied warranty of
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
   Lesser General Public License for more details.

   You should have received a copy of the GNU Lesser General Public
   License along with the GNU C Library.  If not, see
   <http://www.gnu.org/licenses/>.  */

/* Bytewise compare two null-terminated strings of length no longer than N.  */

#include <sysdep.h>

	.set noat
	.set noreorder

/* EV6 only predicts one branch per octaword.  We'll use these to push
   subsequent branches back to the next bundle.  This will generally add
   a fetch+decode cycle to older machines, so skip in that case.  */
#ifdef __alpha_fix__
# define ev6_unop	unop
#else
# define ev6_unop
#endif

	.text

ENTRY(strncmp)
#ifdef PROF
	ldgp	gp, 0(pv)
	lda	AT, _mcount
	jsr	AT, (AT), _mcount
	.prologue 1
#else
	.prologue 0
#endif

	xor	a0, a1, t2	# are s1 and s2 co-aligned?
	beq	a2, $zerolength
	ldq_u	t0, 0(a0)	# load asap to give cache time to catch up
	ldq_u	t1, 0(a1)
	lda	t3, -1
	and	t2, 7, t2
	srl	t3, 1, t6
	and	a0, 7, t4	# find s1 misalignment
	and	a1, 7, t5	# find s2 misalignment
	cmovlt	a2, t6, a2	# bound neg count to LONG_MAX
	addq	a1, a2, a3	# s2+count
	addq	a2, t4, a2	# bias count by s1 misalignment
	and	a2, 7, t10	# ofs of last byte in s1 last word
	srl	a2, 3, a2	# remaining full words in s1 count
	bne	t2, $unaligned

	/* On entry to this basic block:
	   t0 == the first word of s1.
	   t1 == the first word of s2.
	   t3 == -1.  */
$aligned:
	mskqh	t3, a1, t8	# mask off leading garbage
	ornot	t1, t8, t1
	ornot	t0, t8, t0
	cmpbge	zero, t1, t7	# bits set iff null found
	beq	a2, $eoc	# check end of count
	bne	t7, $eos
	beq	t10, $ant_loop

	/* Aligned compare main loop.
	   On entry to this basic block:
	   t0 == an s1 word.
	   t1 == an s2 word not containing a null.  */

	.align 4
$a_loop:
	xor	t0, t1, t2	# e0	:
	bne	t2, $wordcmp	# .. e1 (zdb)
	ldq_u	t1, 8(a1)	# e0    :
	ldq_u	t0, 8(a0)	# .. e1 :

	subq	a2, 1, a2	# e0    :
	addq	a1, 8, a1	# .. e1 :
	addq	a0, 8, a0	# e0    :
	beq	a2, $eoc	# .. e1 :

	cmpbge	zero, t1, t7	# e0    :
	beq	t7, $a_loop	# .. e1 :

	br	$eos

	/* Alternate aligned compare loop, for when there's no trailing
	   bytes on the count.  We have to avoid reading too much data.  */
	.align 4
$ant_loop:
	xor	t0, t1, t2	# e0	:
	ev6_unop
	ev6_unop
	bne	t2, $wordcmp	# .. e1 (zdb)

	subq	a2, 1, a2	# e0    :
	beq	a2, $zerolength	# .. e1 :
	ldq_u	t1, 8(a1)	# e0    :
	ldq_u	t0, 8(a0)	# .. e1 :

	addq	a1, 8, a1	# e0    :
	addq	a0, 8, a0	# .. e1 :
	cmpbge	zero, t1, t7	# e0    :
	beq	t7, $ant_loop	# .. e1 :

	br	$eos

	/* The two strings are not co-aligned.  Align s1 and cope.  */
	/* On entry to this basic block:
	   t0 == the first word of s1.
	   t1 == the first word of s2.
	   t3 == -1.
	   t4 == misalignment of s1.
	   t5 == misalignment of s2.
	  t10 == misalignment of s1 end.  */
	.align	4
$unaligned:
	/* If s1 misalignment is larger than s2 misalignment, we need
	   extra startup checks to avoid SEGV.  */
	subq	a1, t4, a1	# adjust s2 for s1 misalignment
	cmpult	t4, t5, t9
	subq	a3, 1, a3	# last byte of s2
	bic	a1, 7, t8
	mskqh	t3, t5, t7	# mask garbage in s2
	subq	a3, t8, a3
	ornot	t1, t7, t7
	srl	a3, 3, a3	# remaining full words in s2 count
	beq	t9, $u_head

	/* Failing that, we need to look for both eos and eoc within the
	   first word of s2.  If we find either, we can continue by
	   pretending that the next word of s2 is all zeros.  */
	lda	t2, 0		# next = zero
	cmpeq	a3, 0, t8	# eoc in the first word of s2?
	cmpbge	zero, t7, t7	# eos in the first word of s2?
	or	t7, t8, t8
	bne	t8, $u_head_nl

	/* We know just enough now to be able to assemble the first
	   full word of s2.  We can still find a zero at the end of it.

	   On entry to this basic block:
	   t0 == first word of s1
	   t1 == first partial word of s2.</